Wednesday, March 18, 2015

Lab Day 7

Time-varying Signals Lab

In this lab, we focused using an arbitrary  waveform generator to generate time-varying signals and using an oscilloscope to measure time varying signals. This lab introduced the concepts necessary for application, measurement, and interpretation of time-varying signals.

This is the pre-lab, if R1=R2 these are the sketches using the input and output voltages. The top three graphs are the input voltages and the bottom three graphs are the output voltages. 

This is the waveform generator for the sinusoidal waveform. It provides the amplitude , period, and frequency.

This is the oscilloscope window, showing the amplitude , period, and frequency.

This is the waveform generator for the triangular waveform. It provides the amplitude , period, and frequency.


This is the oscilloscope window, showing the amplitude , period, and frequency.


This is the waveform generator for the triangular waveform. It provides the amplitude , period, and frequency.

This is the oscilloscope window, showing the amplitude , period, and frequency.

Conclusion: The graph shows the same images as we did during the pre-lab. The amplitudes for the output voltages are half of the input voltage. 


A BJT Curve Tracer Lab

In this lab, we had to investigate the collector current Ic vs. collector voltage, Vce characteristics of the BJT. We then configure the curve tracer.

This is a picture showing our circuit.

This is the setup from using the Waveforms AWG. Channel 1 which is the top graph is a triangular waveform. Channel 2 is the bottom graph that was put with the information provided by the directions.



This is the oscilloscope window of both graphs.


Using the scope in XY mode, we plotted channel 1 on the horizontal axis and channel 2 on the vertical axis. We see a set of 5 curves of Ic vs. Vce.

Questions Answered:

Ic = (2.5V) / (100ohms) = 0.025 A.
Ib= (2.5V - 0.7V) / (100K ohms) = 1.8 x 10^-5 A.

Vc = (0.025A) * (2.5V) * (2) = 0.125 V
Vb = (1.8 x 10^-5 A) * (2.5V) * (2) = 9 x 10^-5 V.



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